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Author Topic: Math wizards look here.  (Read 14435 times)

YuPony

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Math wizards look here.
« on: November 18, 2010, 02:32:26 pm »

Serious thread now.

I know i've been gone for so long and stuff, bla bla bla xD

But eh. I really need your help with some things.. My maths assignment xD [HAHA, YES SERIOUSLY]

I'm stuck on some parts.

I'll upload the PDF of it for you guys and you can see for yourself

Help will be greatly appreciated, I am deadly serious. Don't be a troll here >.<

[I'm stuck on questions 2,3,6 and 8 :P]

http://www.mediafire.com/?h5cmxbxpuzanawn

Thanks in advance.
« Last Edit: November 18, 2010, 02:51:19 pm by Yupingas »
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Lt. Ragnarok

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I'm a full member, huzzah!
« Reply #1 on: November 18, 2010, 04:44:35 pm »

Fucking magnets, how do they work.

That out of the way:

-I'm pretty sure that 3 is 100 degrees.
-6 seems to be 3.09 units or something. This one was weird, so I'm not completely sure on it.
-8 seems to be 2.60. Again, my math might be a little sketchy due to rounding errors.
-I'm not sure if your teacher's trolling you with 2. If not, I have a sneaking suspicion that it would sum to 1/2 of the rectangle; take that as you will.

PS: Sorry for the lack of work. I'm not especially proficient with mediafire, and I don't care to upload a paint document through Imageshack at the moment.
PPS: Shit, this was harder than my calculus homework. What the hell are you  guys doing?
PPPS: Damn it, these problems wasted my break time.
PPPPS: Who the hell uses commas instead of periods for decimals? Silly non-Americans.
« Last Edit: November 18, 2010, 04:46:58 pm by Phossy »
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YuPony

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Re: I'm a full member, huzzah!
« Reply #2 on: November 18, 2010, 04:59:39 pm »

Fucking magnets, how do they work.

That out of the way:

-I'm pretty sure that 3 is 100 degrees.
-6 seems to be 3.09 units or something. This one was weird, so I'm not completely sure on it.
-8 seems to be 2.60. Again, my math might be a little sketchy due to rounding errors.
-I'm not sure if your teacher's trolling you with 2. If not, I have a sneaking suspicion that it would sum to 1/2 of the rectangle; take that as you will.

PS: Sorry for the lack of work. I'm not especially proficient with mediafire, and I don't care to upload a paint document through Imageshack at the moment.
PPS: Shit, this was harder than my calculus homework. What the hell are you  guys doing?
PPPS: Damn it, these problems wasted my break time.
PPPPS: Who the hell uses commas instead of periods for decimals? Silly non-Americans.


Haha, this is geometry xD
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Velocity

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Re: Math wizards look here.
« Reply #3 on: November 18, 2010, 05:25:51 pm »

This belongs in GD, methinks.
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YuPony

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Re: Math wizards look here.
« Reply #4 on: November 18, 2010, 05:29:05 pm »

Then I request a Move.
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YuPony

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Re: Math wizards look here.
« Reply #5 on: November 19, 2010, 02:37:11 pm »

So I turned in my assignment today.

Hopefully all is well, I skipped some questions but yeah.

I got help from my brother with most of it xD

Wish me luck.

I'll see you whenever I need something else [Lol nah Jk. I'll be on whenever :P]
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Lt. Ragnarok

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Re: Math wizards look here.
« Reply #6 on: November 19, 2010, 03:23:11 pm »

: Oh shit, bro, I hope you didn't use the answers I gave you. • show
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YuPony

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Re: Math wizards look here.
« Reply #7 on: November 19, 2010, 07:28:43 pm »

Dw.

I didn't :3

I actually skipped question 2 and 3 xD

Also 8.

But I did 6.
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Silver

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Re: Math wizards look here.
« Reply #8 on: November 20, 2010, 08:57:09 pm »

2 is impossible without any numbers given.


Also, you already turned it in so I'm not gonna do it :p
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Kudo.

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Re: Math wizards look here.
« Reply #9 on: November 20, 2010, 11:15:31 pm »

2 is impossible without any numbers given.

: About that... • show

Triangle area = 1/2 x base x height
Rectangle area = base x height
Look at it rotated 90 degrees counterclockwise.
Height is always the same for all the triangles (rotated rectangle's new height). Let's call it 'h'
Let's say the bases for all the triangles are a, b, c, and d. a+b+c+d = rotated rectangle's new base. Let's call it /b/ B.
Add their areas: ((h/2) * a) + (h/2) * b) + ((h/2) * c) + ((h/2) * d) = shaded area
Factor it: (h/2) * (a + b + c+ d) = shaded area
Substitute: (h/2) * B = shaded area

Now, let's look at the rectangle's area= h * B

What fraction of the shaded area is the total area= ((h/2) * B) / (h * B)
Simplify: (1/2)/1
The shaded area takes up 1/2 of the rectangle.


._.


3...just from eyeballing it, z would have to be 80 or 100.

On the other hand, I'm too late. Damn.
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Neko Desu

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Re: Math wizards look here.
« Reply #10 on: November 21, 2010, 12:30:35 am »

Can someone here simplify i^(4n + 3)?
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Silver

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Re: Math wizards look here.
« Reply #11 on: November 21, 2010, 12:35:06 am »

2 is impossible without any numbers given.

: About that... • show

Triangle area = 1/2 x base x height
Rectangle area = base x height
Look at it rotated 90 degrees counterclockwise.
Height is always the same for all the triangles (rotated rectangle's new height). Let's call it 'h'
Let's say the bases for all the triangles are a, b, c, and d. a+b+c+d = rotated rectangle's new base. Let's call it /b/ B.
Add their areas: ((h/2) * a) + (h/2) * b) + ((h/2) * c) + ((h/2) * d) = shaded area
Factor it: (h/2) * (a + b + c+ d) = shaded area
Substitute: (h/2) * B = shaded area

Now, let's look at the rectangle's area= h * B

What fraction of the shaded area is the total area= ((h/2) * B) / (h * B)
Simplify: (1/2)/1
The shaded area takes up 1/2 of the rectangle.


._.


3...just from eyeballing it, z would have to be 80 or 100.

On the other hand, I'm too late. Damn.
I'm an idiot. My bad.
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Kudo.

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Re: Math wizards look here.
« Reply #12 on: November 21, 2010, 12:38:34 am »

Can someone here simplify i^(4n + 3)?

Assuming "i" is the term for imaginary number: sq rt (-1)
and assuming n = any integer
i^(4n + 3) = -i

If not assuming, it's already simplified.

2 is impossible without any numbers given.

: About that... • show

Triangle area = 1/2 x base x height
Rectangle area = base x height
Look at it rotated 90 degrees counterclockwise.
Height is always the same for all the triangles (rotated rectangle's new height). Let's call it 'h'
Let's say the bases for all the triangles are a, b, c, and d. a+b+c+d = rotated rectangle's new base. Let's call it /b/ B.
Add their areas: ((h/2) * a) + (h/2) * b) + ((h/2) * c) + ((h/2) * d) = shaded area
Factor it: (h/2) * (a + b + c+ d) = shaded area
Substitute: (h/2) * B = shaded area

Now, let's look at the rectangle's area= h * B

What fraction of the shaded area is the total area= ((h/2) * B) / (h * B)
Simplify: (1/2)/1
The shaded area takes up 1/2 of the rectangle.


._.


3...just from eyeballing it, z would have to be 80 or 100.

On the other hand, I'm too late. Damn.
I'm an idiot. My bad.
It's alright, I was skeptical of it's possibility myself until I worked it out.
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Kwiftee

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Re: Math wizards look here.
« Reply #13 on: November 21, 2010, 12:42:24 am »

i^(4n+3) where n∈Z, I assume?
=i^(4n)*i^3
=1*-i
=-i

Ninja'd: DAMNIT KUDO

Also I'm bored, so someone simplify (tan(x)+sec(x)+1)(tan(x)-sec(x)+1).
« Last Edit: November 21, 2010, 12:44:44 am by Kwiftee »
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Neko Desu

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Re: Math wizards look here.
« Reply #14 on: November 21, 2010, 12:43:29 am »

i^(4n + 3)
= i^4n(i^3)
= [(i^4)^n](-i)
= (1^n)(-i)
= -i

You are correct!  :D

thanks for checking my homework
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